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cl-lexer: Hack around ambiguity between 1.0 and 1..0

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This requires more than one token lookahead, but is already part of a hack itself, so... /shrug
This commit is contained in:
John 2024-09-19 14:02:02 -05:00
parent 94be5d787f
commit f4fe07a08b
1 changed files with 6 additions and 2 deletions
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8
compiler/cl-lexer/src/lib.rs
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@ -378,18 +378,22 @@ impl<'t> Lexer<'t> {
Ok('d') => self.consume()?.digits::<10>(),
Ok('o') => self.consume()?.digits::<8>(),
Ok('b') => self.consume()?.digits::<2>(),
Ok('0'..='9') => self.digits::<10>(),
Ok('0'..='9' | '.') => self.digits::<10>(),
_ => self.produce(Kind::Literal, 0),
}
}
fn digits<const B: u32>(&mut self) -> LResult<Token> {
let mut value = self.digit::<B>()? as u128;
let mut value = 0;
while let Ok(true) = self.peek().as_ref().map(char::is_ascii_alphanumeric) {
value = value * B as u128 + self.digit::<B>()? as u128;
}
// TODO: find a better way to handle floats in the tokenizer
match self.peek() {
Ok('.') => {
// FIXME: hack: 0.. is not [0.0, '.']
if let Ok('.') = self.clone().consume()?.next() {
return self.produce(Kind::Literal, value);
}
let mut float = format!("{value}.");
self.consume()?;
while let Ok(true) = self.peek().as_ref().map(char::is_ascii_digit) {